以因式分解:
3x²-x+1
=3(x- 1/6+√11i/6)(x- 1/6 -√11i/6)
3X^2+X-1
=3(X^2+2*1/6*X+1/36-1/36-1/3)
=3[(X+1/6)^2-13/36]
=3(X+1/6-√13/6)(X+1/6+√13/6)
3x平方-x+1怎么解急求答案,帮忙回答下
以因式分解:
3x²-x+1
=3(x- 1/6+√11i/6)(x- 1/6 -√11i/6)
3X^2+X-1
=3(X^2+2*1/6*X+1/36-1/36-1/3)
=3[(X+1/6)^2-13/36]
=3(X+1/6-√13/6)(X+1/6+√13/6)